Tugas Menghitung Jumlah Network Dan HostNama : Jaradot Mangihut Davied
NIM : 12211206
Kelas : 12.4B.31
Hitunglah jumlah Network dan Host yang akanterbentuk dari alamat IP Address dibawah ini, kemudian buat rincian alamat (Network, Broadcast) beserta alamat yang dapat diberikan kepada setiap host (minimal untuk 5 host/komputer):
1. 192.168.10.1/30
2. 172.168.10.1/16
3. 172.168.10.0/22
4. 10.168.5.1/8
5. 10.168.5.1/17
Jawab :
1) 192.168.10.1/30
Netmask = 255.255.255.252
Subnet = 11111111.11111111.11111111.11111100 : /30
Network = 2n = 26 = 64 network
Host = 2h-2 = 22-2 = 2 host
Alokasi IP :
Network : 192.168.10.0
Host : 192.168.10.1 - 192.168.10.2
Broadcast : 192.168.10.3
Network :192.168.10.4
Host : 192.168.10.5 - 192.168.10.6
Broadcast : 192.168.10.7
Network :192.168.10.8
Host : 192.168.10.9 - 192.168.10.10
Broadcast : 192.168.10.11
2) 172.168.10.1/16
Netmask = 255.255.000.000
Subnet = 11111111.11111111.00000000.00000000 : /16
Network = 2n = 20 = 1 network
Host = 2h-2 = 216-2 = 65.534 host
Alokasi IP :
Network :172.168.0.0
Host : 172.168.0.1 - 192.168.255.254
Broadcast : 192.168.255.255
3) 172.168.10.0/22
Netmask = 255.255.252.000
Subnet = 11111111.11111111.11111100.00000000 : /22
Network = 2n = 26 = 64 network
Host = 2h-2 = 210-2 = 1.022 host
Alokasi IP :
Network :172.168.10.0
Host : 172.168.10.1 - 192.168.255.254
Broadcast : 192.168.255.255
4) 10.168.5.1/8
Netmask = 255.000.000.000
Subnet = 11111111.00000000.00000000.00000000 : /8
Network = 2n = 20 = 1 network
Host = 2h-2 = 224-2 = 167.772.614 host
Alokasi IP :
Network :10.168.5.0
Host : 10.0.0.1 - 10.255.255.254
Broadcast : 10.255.255.255
5) 10.168.5.1/17
Netmask = 255.255.128.000
Subnet = 11111111.11111111.10000000.00000000 : /17
Network = 2n = 21 = 2 network
Host = 2h-2 = 215-2 = 32.766 host
Alokasi IP :
Network :10.168.0.0
Host : 10.168.0.1 - 10.168.127.254
Broadcast : 10.168.127.255
Terima kasih dan semoga bermanfaat
Penulis : Jaradot
